Base | Representation |
---|---|
bin | 1010011101001101111101… |
… | …1000101011111000110011 |
3 | 1111201002222021212222002211 |
4 | 2213103133120223320303 |
5 | 3001332010022240413 |
6 | 40241404042552551 |
7 | 2264431236615466 |
oct | 247233730537063 |
9 | 44632867788084 |
10 | 11497080274483 |
11 | 37329800a5411 |
12 | 1358264b08757 |
13 | 6552296b589b |
14 | 2ba666acb2dd |
15 | 14e0ead0383d |
hex | a74df62be33 |
11497080274483 has 2 divisors, whose sum is σ = 11497080274484. Its totient is φ = 11497080274482.
The previous prime is 11497080274481. The next prime is 11497080274513. The reversal of 11497080274483 is 38447208079411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11497080274483 - 21 = 11497080274481 is a prime.
Together with 11497080274481, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11497080274481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5748540137241 + 5748540137242.
It is an arithmetic number, because the mean of its divisors is an integer number (5748540137242).
Almost surely, 211497080274483 is an apocalyptic number.
11497080274483 is a deficient number, since it is larger than the sum of its proper divisors (1).
11497080274483 is an equidigital number, since it uses as much as digits as its factorization.
11497080274483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10838016, while the sum is 58.
The spelling of 11497080274483 in words is "eleven trillion, four hundred ninety-seven billion, eighty million, two hundred seventy-four thousand, four hundred eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •