Base | Representation |
---|---|
bin | 1010011101001101111101… |
… | …1000101011111001010001 |
3 | 1111201002222021212222010221 |
4 | 2213103133120223321101 |
5 | 3001332010022241023 |
6 | 40241404042553041 |
7 | 2264431236615541 |
oct | 247233730537121 |
9 | 44632867788127 |
10 | 11497080274513 |
11 | 37329800a5439 |
12 | 1358264b08781 |
13 | 6552296b58c2 |
14 | 2ba666acb321 |
15 | 14e0ead0385d |
hex | a74df62be51 |
11497080274513 has 2 divisors, whose sum is σ = 11497080274514. Its totient is φ = 11497080274512.
The previous prime is 11497080274483. The next prime is 11497080274607. The reversal of 11497080274513 is 31547208079411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10218839742864 + 1278240531649 = 3196692^2 + 1130593^2 .
It is a cyclic number.
It is not a de Polignac number, because 11497080274513 - 25 = 11497080274481 is a prime.
It is not a weakly prime, because it can be changed into another prime (11497080274213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5748540137256 + 5748540137257.
It is an arithmetic number, because the mean of its divisors is an integer number (5748540137257).
Almost surely, 211497080274513 is an apocalyptic number.
It is an amenable number.
11497080274513 is a deficient number, since it is larger than the sum of its proper divisors (1).
11497080274513 is an equidigital number, since it uses as much as digits as its factorization.
11497080274513 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1693440, while the sum is 52.
The spelling of 11497080274513 in words is "eleven trillion, four hundred ninety-seven billion, eighty million, two hundred seventy-four thousand, five hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.106 sec. • engine limits •