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1150025137493 is a prime number
BaseRepresentation
bin10000101111000010110…
…101101111110101010101
311001221102020012001111212
4100233002311233311111
5122320222413344433
62240151513511205
7146041460244311
oct20570265576525
94057366161455
101150025137493
114037a5233231
12166a71112505
13845a6b0994b
143d93929cb41
151edac65dd48
hex10bc2d6fd55

1150025137493 has 2 divisors, whose sum is σ = 1150025137494. Its totient is φ = 1150025137492.

The previous prime is 1150025137487. The next prime is 1150025137507. The reversal of 1150025137493 is 3947315200511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 889763952529 + 260261184964 = 943273^2 + 510158^2 .

It is a cyclic number.

It is not a de Polignac number, because 1150025137493 - 28 = 1150025137237 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1150025137493.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1150025137403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575012568746 + 575012568747.

It is an arithmetic number, because the mean of its divisors is an integer number (575012568747).

Almost surely, 21150025137493 is an apocalyptic number.

It is an amenable number.

1150025137493 is a deficient number, since it is larger than the sum of its proper divisors (1).

1150025137493 is an equidigital number, since it uses as much as digits as its factorization.

1150025137493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 113400, while the sum is 41.

The spelling of 1150025137493 in words is "one trillion, one hundred fifty billion, twenty-five million, one hundred thirty-seven thousand, four hundred ninety-three".