Base | Representation |
---|---|
bin | 10101011010111110… |
… | …00111110010100011 |
3 | 1002200111022112120121 |
4 | 22231133013302203 |
5 | 142023120120311 |
6 | 5141104421111 |
7 | 554665034113 |
oct | 125537076243 |
9 | 32614275517 |
10 | 11500551331 |
11 | 4971841485 |
12 | 228b617797 |
13 | 1113843679 |
14 | 7b156b043 |
15 | 4749b5b71 |
hex | 2ad7c7ca3 |
11500551331 has 2 divisors, whose sum is σ = 11500551332. Its totient is φ = 11500551330.
The previous prime is 11500551329. The next prime is 11500551347. The reversal of 11500551331 is 13315500511.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11500551331 - 21 = 11500551329 is a prime.
It is a super-2 number, since 2×115005513312 (a number of 21 digits) contains 22 as substring.
Together with 11500551329, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 11500551296 and 11500551305.
It is not a weakly prime, because it can be changed into another prime (11500551371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5750275665 + 5750275666.
It is an arithmetic number, because the mean of its divisors is an integer number (5750275666).
Almost surely, 211500551331 is an apocalyptic number.
11500551331 is a deficient number, since it is larger than the sum of its proper divisors (1).
11500551331 is an equidigital number, since it uses as much as digits as its factorization.
11500551331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1125, while the sum is 25.
The spelling of 11500551331 in words is "eleven billion, five hundred million, five hundred fifty-one thousand, three hundred thirty-one".
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