1150100000115 has 64 divisors (see below), whose sum is σ = 2057747328000. Its totient is φ = 543669708800.

The previous prime is 1150100000083. The next prime is 1150100000149. The reversal of 1150100000115 is 5110000010511.

It is not a de Polignac number, because 1150100000115 - 2⁵ = 1150100000083 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a junction number, because it is equal to n+sod(n) for n = 1150100000094 and 1150100000103.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 10492111 + ... + 10601159.

It is an arithmetic number, because the mean of its divisors is an integer number (32152302000).

Almost surely, 2^{1150100000115} is an apocalyptic number.

1150100000115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

1150100000115 is a deficient number, since it is larger than the sum of its proper divisors (907647327885).

1150100000115 is a wasteful number, since it uses less digits than its factorization.

1150100000115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 110668.

The product of its (nonzero) digits is 25, while the sum is 15.

Adding to 1150100000115 its reverse (5110000010511), we get a palindrome (6260100010626).

The spelling of 1150100000115 in words is "one trillion, one hundred fifty billion, one hundred million, one hundred fifteen", and thus it is an aban number.