11502512314045 has 4 divisors (see below), whose sum is σ = 13803014776860. Its totient is φ = 9202009851232.

The previous prime is 11502512314043. The next prime is 11502512314049. The reversal of 11502512314045 is 54041321520511.

11502512314045 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3134804809444 + 8367707504601 = 1770538^2 + 2892699^2 .

It is a cyclic number.

It is not a de Polignac number, because 11502512314045 - 2¹ = 11502512314043 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11502512314045.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11502512314043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1150251231400 + ... + 1150251231409.

It is an arithmetic number, because the mean of its divisors is an integer number (3450753694215).

Almost surely, 2^{11502512314045} is an apocalyptic number.

It is an amenable number.

11502512314045 is a deficient number, since it is larger than the sum of its proper divisors (2300502462815).

11502512314045 is an equidigital number, since it uses as much as digits as its factorization.

11502512314045 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2300502462814.

The product of its (nonzero) digits is 24000, while the sum is 34.

Adding to 11502512314045 its reverse (54041321520511), we get a palindrome (65543833834556).

The spelling of 11502512314045 in words is "eleven trillion, five hundred two billion, five hundred twelve million, three hundred fourteen thousand, forty-five".