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1150305325301 = 11210392297627
BaseRepresentation
bin10000101111010011100…
…010100101000011110101
311001222010202102001221002
4100233103202211003311
5122321311130402201
62240235403133045
7146051431636346
oct20572342450365
94058122361832
101150305325301
11403929405500
12166b2ab14185
138461cb8b952
143d9645960cd
151edc705776b
hex10bd38a50f5

1150305325301 has 12 divisors (see below), whose sum is σ = 1276660790496. Its totient is φ = 1035579363720.

The previous prime is 1150305325291. The next prime is 1150305325303. The reversal of 1150305325301 is 1035235030511.

It is a happy number.

It is not a de Polignac number, because 1150305325301 - 222 = 1150301130997 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1150305325303) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 46136351 + ... + 46161276.

It is an arithmetic number, because the mean of its divisors is an integer number (106388399208).

Almost surely, 21150305325301 is an apocalyptic number.

1150305325301 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1150305325301 is a deficient number, since it is larger than the sum of its proper divisors (126355465195).

1150305325301 is a wasteful number, since it uses less digits than its factorization.

1150305325301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 92297752 (or 92297741 counting only the distinct ones).

The product of its (nonzero) digits is 6750, while the sum is 29.

The spelling of 1150305325301 in words is "one trillion, one hundred fifty billion, three hundred five million, three hundred twenty-five thousand, three hundred one".

Divisors: 1 11 103 121 1133 12463 92297627 1015273897 9506655581 11168012867 104573211391 1150305325301