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11503055077 is a prime number
BaseRepresentation
bin10101011011010001…
…01011000011100101
31002200200000202001221
422231220223003211
5142024240230302
65141234220341
7555025232503
oct125550530345
932620022057
1011503055077
1149731a1598
1222904246b1
13111420c187
147b1a1d673
15474d0c937
hex2ada2b0e5

11503055077 has 2 divisors, whose sum is σ = 11503055078. Its totient is φ = 11503055076.

The previous prime is 11503055071. The next prime is 11503055089. The reversal of 11503055077 is 77055030511.

11503055077 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6997155201 + 4505899876 = 83649^2 + 67126^2 .

It is a cyclic number.

It is not a de Polignac number, because 11503055077 - 215 = 11503022309 is a prime.

It is a super-2 number, since 2×115030550772 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11503055071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5751527538 + 5751527539.

It is an arithmetic number, because the mean of its divisors is an integer number (5751527539).

Almost surely, 211503055077 is an apocalyptic number.

It is an amenable number.

11503055077 is a deficient number, since it is larger than the sum of its proper divisors (1).

11503055077 is an equidigital number, since it uses as much as digits as its factorization.

11503055077 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18375, while the sum is 34.

Adding to 11503055077 its reverse (77055030511), we get a palindrome (88558085588).

The spelling of 11503055077 in words is "eleven billion, five hundred three million, fifty-five thousand, seventy-seven".