11503115134 has 16 divisors (see below), whose sum is σ = 19742496768. Its totient is φ = 4924188792.

The previous prime is 11503115101. The next prime is 11503115137. The reversal of 11503115134 is 43151130511.

It is a super-3 number, since 3×11503115134³ (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11503115099 and 11503115108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11503115137) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 463962 + ... + 488125.

It is an arithmetic number, because the mean of its divisors is an integer number (1233906048).

Almost surely, 2^11503115134 is an apocalyptic number.

11503115134 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

11503115134 is a deficient number, since it is larger than the sum of its proper divisors (8239381634).

11503115134 is an equidigital number, since it uses as much as digits as its factorization.

11503115134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 952959.

The product of its (nonzero) digits is 900, while the sum is 25.

Adding to 11503115134 its reverse (43151130511), we get a palindrome (54654245645).

The spelling of 11503115134 in words is "eleven billion, five hundred three million, one hundred fifteen thousand, one hundred thirty-four".