11503115133 has 4 divisors (see below), whose sum is σ = 15337486848. Its totient is φ = 7668743420.

The previous prime is 11503115101. The next prime is 11503115137. The reversal of 11503115133 is 33151130511.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11503115133 - 2⁵ = 11503115101 is a prime.

It is a super-3 number, since 3×11503115133³ (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11503115137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1917185853 + ... + 1917185858.

It is an arithmetic number, because the mean of its divisors is an integer number (3834371712).

Almost surely, 2^11503115133 is an apocalyptic number.

It is an amenable number.

11503115133 is a deficient number, since it is larger than the sum of its proper divisors (3834371715).

11503115133 is an equidigital number, since it uses as much as digits as its factorization.

11503115133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3834371714.

The product of its (nonzero) digits is 675, while the sum is 24.

Adding to 11503115133 its reverse (33151130511), we get a palindrome (44654245644).

The spelling of 11503115133 in words is "eleven billion, five hundred three million, one hundred fifteen thousand, one hundred thirty-three".