115034119 has 2 divisors, whose sum is σ = 115034120. Its totient is φ = 115034118.

The previous prime is 115034111. The next prime is 115034141. The reversal of 115034119 is 911430511.

It is a weak prime.

It is an emirp because it is prime and its reverse (911430511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115034119 - 2³ = 115034111 is a prime.

It is a super-2 number, since 2×115034119² = 26465697068212322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 115034093 and 115034102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115034111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57517059 + 57517060.

It is an arithmetic number, because the mean of its divisors is an integer number (57517060).

Almost surely, 2^115034119 is an apocalyptic number.

115034119 is a deficient number, since it is larger than the sum of its proper divisors (1).

115034119 is an equidigital number, since it uses as much as digits as its factorization.

115034119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 25.

The square root of 115034119 is about 10725.3959833658. The cubic root of 115034119 is about 486.3425007572.

The spelling of 115034119 in words is "one hundred fifteen million, thirty-four thousand, one hundred nineteen".