115040234121151 has 4 divisors (see below), whose sum is σ = 115081275948472. Its totient is φ = 114999192293832.

The previous prime is 115040234121107. The next prime is 115040234121199. The reversal of 115040234121151 is 151121432040511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 115040234121151 - 2¹⁵ = 115040234088383 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115040234121101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20520909456 + ... + 20520915061.

It is an arithmetic number, because the mean of its divisors is an integer number (28770318987118).

Almost surely, 2^{115040234121151} is an apocalyptic number.

115040234121151 is a deficient number, since it is larger than the sum of its proper divisors (41041827321).

115040234121151 is an equidigital number, since it uses as much as digits as its factorization.

115040234121151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41041827320.

The product of its (nonzero) digits is 4800, while the sum is 31.

Adding to 115040234121151 its reverse (151121432040511), we get a palindrome (266161666161662).

The spelling of 115040234121151 in words is "one hundred fifteen trillion, forty billion, two hundred thirty-four million, one hundred twenty-one thousand, one hundred fifty-one".