11505000130031 has 2 divisors, whose sum is σ = 11505000130032. Its totient is φ = 11505000130030.

The previous prime is 11505000130009. The next prime is 11505000130033. The reversal of 11505000130031 is 13003100050511.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11505000130031 is a prime.

It is a super-2 number, since 2×11505000130031² (a number of 27 digits) contains 22 as substring.

Together with 11505000130033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11505000129985 and 11505000130012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11505000130033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5752500065015 + 5752500065016.

It is an arithmetic number, because the mean of its divisors is an integer number (5752500065016).

Almost surely, 2^{11505000130031} is an apocalyptic number.

11505000130031 is a deficient number, since it is larger than the sum of its proper divisors (1).

11505000130031 is an equidigital number, since it uses as much as digits as its factorization.

11505000130031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 225, while the sum is 20.

Adding to 11505000130031 its reverse (13003100050511), we get a palindrome (24508100180542).

The spelling of 11505000130031 in words is "eleven trillion, five hundred five billion, one hundred thirty thousand, thirty-one".