Base | Representation |
---|---|
bin | 1010011101101011111111… |
… | …0010010011110000111111 |
3 | 1111201212202222210020121011 |
4 | 2213122333302103300333 |
5 | 3002000011323230403 |
6 | 40245215520020051 |
7 | 2265135044620252 |
oct | 247327762236077 |
9 | 44655688706534 |
10 | 11505140055103 |
11 | 3736336693932 |
12 | 1359934161627 |
13 | 655c12429b46 |
14 | 2babcd2b7099 |
15 | 14e41d6aba6d |
hex | a76bfc93c3f |
11505140055103 has 4 divisors (see below), whose sum is σ = 11816089786360. Its totient is φ = 11194190323848.
The previous prime is 11505140055061. The next prime is 11505140055379. The reversal of 11505140055103 is 30155004150511.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11505140055103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11505140053103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 155474865573 + ... + 155474865646.
It is an arithmetic number, because the mean of its divisors is an integer number (2954022446590).
Almost surely, 211505140055103 is an apocalyptic number.
11505140055103 is a deficient number, since it is larger than the sum of its proper divisors (310949731257).
11505140055103 is an equidigital number, since it uses as much as digits as its factorization.
11505140055103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 310949731256.
The product of its (nonzero) digits is 7500, while the sum is 31.
The spelling of 11505140055103 in words is "eleven trillion, five hundred five billion, one hundred forty million, fifty-five thousand, one hundred three".
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