Base | Representation |
---|---|
bin | 110101100100111000… |
… | …0010011110101111111 |
3 | 101222222022110112001202 |
4 | 1223021300103311333 |
5 | 3341112313044203 |
6 | 124504411130115 |
7 | 11212101104225 |
oct | 1531160236577 |
9 | 358868415052 |
10 | 115054034303 |
11 | 4488100396a |
12 | 1a36b44393b |
13 | ab075c7250 |
14 | 57d650cb15 |
15 | 2ed5b74388 |
hex | 1ac9c13d7f |
115054034303 has 4 divisors (see below), whose sum is σ = 123904344648. Its totient is φ = 106203723960.
The previous prime is 115054034267. The next prime is 115054034309. The reversal of 115054034303 is 303430450511.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 115054034303 - 220 = 115052985727 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115054034309) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4425155153 + ... + 4425155178.
It is an arithmetic number, because the mean of its divisors is an integer number (30976086162).
Almost surely, 2115054034303 is an apocalyptic number.
115054034303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
115054034303 is a deficient number, since it is larger than the sum of its proper divisors (8850310345).
115054034303 is an equidigital number, since it uses as much as digits as its factorization.
115054034303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8850310344.
The product of its (nonzero) digits is 10800, while the sum is 29.
Adding to 115054034303 its reverse (303430450511), we get a palindrome (418484484814).
The spelling of 115054034303 in words is "one hundred fifteen billion, fifty-four million, thirty-four thousand, three hundred three".
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