Base | Representation |
---|---|
bin | 1010011101101101001001… |
… | …0010101001001100111111 |
3 | 1111201220120121222120022011 |
4 | 2213123102102221030333 |
5 | 3002001130313141112 |
6 | 40245310410232051 |
7 | 2265145534550653 |
oct | 247332222511477 |
9 | 44656517876264 |
10 | 11505450521407 |
11 | 3736485966857 |
12 | 1359a00125627 |
13 | 655c6185080b |
14 | 2bac1c612a63 |
15 | 14e43aa86aa7 |
hex | a76d24a933f |
11505450521407 has 2 divisors, whose sum is σ = 11505450521408. Its totient is φ = 11505450521406.
The previous prime is 11505450521401. The next prime is 11505450521429. The reversal of 11505450521407 is 70412505450511.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11505450521407 - 215 = 11505450488639 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11505450521407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11505450521401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5752725260703 + 5752725260704.
It is an arithmetic number, because the mean of its divisors is an integer number (5752725260704).
Almost surely, 211505450521407 is an apocalyptic number.
11505450521407 is a deficient number, since it is larger than the sum of its proper divisors (1).
11505450521407 is an equidigital number, since it uses as much as digits as its factorization.
11505450521407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 140000, while the sum is 40.
Adding to 11505450521407 its reverse (70412505450511), we get a palindrome (81917955971918).
The spelling of 11505450521407 in words is "eleven trillion, five hundred five billion, four hundred fifty million, five hundred twenty-one thousand, four hundred seven".
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