11509931 has 2 divisors, whose sum is σ = 11509932. Its totient is φ = 11509930.

The previous prime is 11509921. The next prime is 11509933. The reversal of 11509931 is 13990511.

It is a strong prime.

It is an emirp because it is prime and its reverse (13990511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11509931 - 2¹⁸ = 11247787 is a prime.

It is a super-2 number, since 2×11509931² = 264957023249522, which contains 22 as substring.

Together with 11509933, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11509894 and 11509903.

It is not a weakly prime, because it can be changed into another prime (11509933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5754965 + 5754966.

It is an arithmetic number, because the mean of its divisors is an integer number (5754966).

Almost surely, 2^11509931 is an apocalyptic number.

11509931 is a deficient number, since it is larger than the sum of its proper divisors (1).

11509931 is an equidigital number, since it uses as much as digits as its factorization.

11509931 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1215, while the sum is 29.

The square root of 11509931 is about 3392.6289216476. The cubic root of 11509931 is about 225.7828271139.

The spelling of 11509931 in words is "eleven million, five hundred nine thousand, nine hundred thirty-one".