115101403113493 has 2 divisors, whose sum is σ = 115101403113494. Its totient is φ = 115101403113492.

The previous prime is 115101403113397. The next prime is 115101403113517. The reversal of 115101403113493 is 394311304101511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 92568894140529 + 22532508972964 = 9621273^2 + 4746842^2 .

It is an emirp because it is prime and its reverse (394311304101511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115101403113493 - 2⁹ = 115101403112981 is a prime.

It is a super-2 number, since 2×115101403113493² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115101403113293) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57550701556746 + 57550701556747.

It is an arithmetic number, because the mean of its divisors is an integer number (57550701556747).

Almost surely, 2^{115101403113493} is an apocalyptic number.

It is an amenable number.

115101403113493 is a deficient number, since it is larger than the sum of its proper divisors (1).

115101403113493 is an equidigital number, since it uses as much as digits as its factorization.

115101403113493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19440, while the sum is 37.

The spelling of 115101403113493 in words is "one hundred fifteen trillion, one hundred one billion, four hundred three million, one hundred thirteen thousand, four hundred ninety-three".