11510401341 has 4 divisors (see below), whose sum is σ = 15347201792. Its totient is φ = 7673600892.

The previous prime is 11510401321. The next prime is 11510401349. The reversal of 11510401341 is 14310401511.

11510401341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 11510401341 - 2¹³ = 11510393149 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11510401349) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1918400221 + ... + 1918400226.

It is an arithmetic number, because the mean of its divisors is an integer number (3836800448).

Almost surely, 2^11510401341 is an apocalyptic number.

It is an amenable number.

11510401341 is a deficient number, since it is larger than the sum of its proper divisors (3836800451).

11510401341 is an equidigital number, since it uses as much as digits as its factorization.

11510401341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3836800450.

The product of its (nonzero) digits is 240, while the sum is 21.

Adding to 11510401341 its reverse (14310401511), we get a palindrome (25820802852).

The spelling of 11510401341 in words is "eleven billion, five hundred ten million, four hundred one thousand, three hundred forty-one".