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11511083201 is a prime number
BaseRepresentation
bin10101011100001110…
…10011000011000001
31002201020010121120212
422232013103003001
5142033314130301
65142122243505
7555153410222
oct125607230301
932636117525
1011511083201
114977785202
122293056595
131115a90347
147b2b0d249
154758964bb
hex2ae1d30c1

11511083201 has 2 divisors, whose sum is σ = 11511083202. Its totient is φ = 11511083200.

The previous prime is 11511083147. The next prime is 11511083203. The reversal of 11511083201 is 10238011511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9797040400 + 1714042801 = 98980^2 + 41401^2 .

It is a cyclic number.

It is not a de Polignac number, because 11511083201 - 214 = 11511066817 is a prime.

Together with 11511083203, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11511083203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5755541600 + 5755541601.

It is an arithmetic number, because the mean of its divisors is an integer number (5755541601).

Almost surely, 211511083201 is an apocalyptic number.

It is an amenable number.

11511083201 is a deficient number, since it is larger than the sum of its proper divisors (1).

11511083201 is an equidigital number, since it uses as much as digits as its factorization.

11511083201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 240, while the sum is 23.

Adding to 11511083201 its reverse (10238011511), we get a palindrome (21749094712).

The spelling of 11511083201 in words is "eleven billion, five hundred eleven million, eighty-three thousand, two hundred one".