Base | Representation |
---|---|
bin | 11010001011000111011000… |
… | …101000111010011110100011 |
3 | 120002120200220121000122021120 |
4 | 122023013120220322132203 |
5 | 110042003013043312120 |
6 | 1044454112340423323 |
7 | 33150433524021300 |
oct | 3213073050723643 |
9 | 502520817018246 |
10 | 115113053104035 |
11 | 33751198539038 |
12 | 10ab18206a7b43 |
13 | 4c3016424b04c |
14 | 205d7041780a7 |
15 | d4954c0b0140 |
hex | 68b1d8a3a7a3 |
115113053104035 has 24 divisors (see below), whose sum is σ = 214251233533776. Its totient is φ = 52623109990080.
The previous prime is 115113053103977. The next prime is 115113053104043. The reversal of 115113053104035 is 530401350311511.
It is not a de Polignac number, because 115113053104035 - 212 = 115113053099939 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 115113053103987 and 115113053104005.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 78308198656 + ... + 78308200125.
It is an arithmetic number, because the mean of its divisors is an integer number (8927134730574).
Almost surely, 2115113053104035 is an apocalyptic number.
115113053104035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
115113053104035 is a deficient number, since it is larger than the sum of its proper divisors (99138180429741).
115113053104035 is a wasteful number, since it uses less digits than its factorization.
115113053104035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 156616398803 (or 156616398796 counting only the distinct ones).
The product of its (nonzero) digits is 13500, while the sum is 33.
The spelling of 115113053104035 in words is "one hundred fifteen trillion, one hundred thirteen billion, fifty-three million, one hundred four thousand, thirty-five".
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