Search a number
-
+
115114403 = 590319501
BaseRepresentation
bin1101101110010…
…00000110100011
322000121102021102
412313020012203
5213432130103
615231145015
72565312335
oct667100643
9260542242
10115114403
1159a85178
123267516b
131ab06241
1411407455
15a18ce88
hex6dc81a3

115114403 has 4 divisors (see below), whose sum is σ = 115139808. Its totient is φ = 115089000.

The previous prime is 115114399. The next prime is 115114409. The reversal of 115114403 is 304411511.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 115114403 - 22 = 115114399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (115114409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3848 + ... + 15653.

It is an arithmetic number, because the mean of its divisors is an integer number (28784952).

Almost surely, 2115114403 is an apocalyptic number.

115114403 is a deficient number, since it is larger than the sum of its proper divisors (25405).

115114403 is an equidigital number, since it uses as much as digits as its factorization.

115114403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25404.

The product of its (nonzero) digits is 240, while the sum is 20.

The square root of 115114403 is about 10729.1380362078. The cubic root of 115114403 is about 486.4556163027.

Adding to 115114403 its reverse (304411511), we get a palindrome (419525914).

The spelling of 115114403 in words is "one hundred fifteen million, one hundred fourteen thousand, four hundred three".

Divisors: 1 5903 19501 115114403