Base | Representation |
---|---|
bin | 110101100110101011… |
… | …0100111010111011111 |
3 | 102000010112001210101001 |
4 | 1223031112213113133 |
5 | 3341223242014031 |
6 | 124514405131131 |
7 | 11213433214114 |
oct | 1531526472737 |
9 | 360115053331 |
10 | 115114407391 |
11 | 4490209a085 |
12 | 1a3876b9aa7 |
13 | ab16c74c79 |
14 | 580054690b |
15 | 2edb0ec861 |
hex | 1acd5a75df |
115114407391 has 2 divisors, whose sum is σ = 115114407392. Its totient is φ = 115114407390.
The previous prime is 115114407389. The next prime is 115114407407. The reversal of 115114407391 is 193704411511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 115114407391 - 21 = 115114407389 is a prime.
It is a super-2 number, since 2×1151144073912 (a number of 23 digits) contains 22 as substring.
Together with 115114407389, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 115114407391.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115114407341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57557203695 + 57557203696.
It is an arithmetic number, because the mean of its divisors is an integer number (57557203696).
Almost surely, 2115114407391 is an apocalyptic number.
115114407391 is a deficient number, since it is larger than the sum of its proper divisors (1).
115114407391 is an equidigital number, since it uses as much as digits as its factorization.
115114407391 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 37.
The spelling of 115114407391 in words is "one hundred fifteen billion, one hundred fourteen million, four hundred seven thousand, three hundred ninety-one".
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