115114433 has 4 divisors (see below), whose sum is σ = 131559360. Its totient is φ = 98669508.

The previous prime is 115114423. The next prime is 115114453. The reversal of 115114433 is 334411511.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 334411511 = 7 ⋅47773073.

It is not a de Polignac number, because 115114433 - 2¹² = 115110337 is a prime.

It is a super-2 number, since 2×115114433² = 26502665369822978, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 115114399 and 115114408.

It is not an unprimeable number, because it can be changed into a prime (115114423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8222453 + ... + 8222466.

It is an arithmetic number, because the mean of its divisors is an integer number (32889840).

Almost surely, 2^115114433 is an apocalyptic number.

It is an amenable number.

115114433 is a deficient number, since it is larger than the sum of its proper divisors (16444927).

115114433 is an equidigital number, since it uses as much as digits as its factorization.

115114433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16444926.

The product of its digits is 720, while the sum is 23.

The square root of 115114433 is about 10729.1394342696. The cubic root of 115114433 is about 486.4556585612.

Adding to 115114433 its reverse (334411511), we get a palindrome (449525944).

The spelling of 115114433 in words is "one hundred fifteen million, one hundred fourteen thousand, four hundred thirty-three".