11512023401 has 2 divisors, whose sum is σ = 11512023402. Its totient is φ = 11512023400.

The previous prime is 11512023343. The next prime is 11512023403. The reversal of 11512023401 is 10432021511.

11512023401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9619686400 + 1892337001 = 98080^2 + 43501^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11512023401 is a prime.

Together with 11512023403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11512023403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5756011700 + 5756011701.

It is an arithmetic number, because the mean of its divisors is an integer number (5756011701).

Almost surely, 2^11512023401 is an apocalyptic number.

It is an amenable number.

11512023401 is a deficient number, since it is larger than the sum of its proper divisors (1).

11512023401 is an equidigital number, since it uses as much as digits as its factorization.

11512023401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 11512023401 its reverse (10432021511), we get a palindrome (21944044912).

The spelling of 11512023401 in words is "eleven billion, five hundred twelve million, twenty-three thousand, four hundred one".