115122113542141 has 4 divisors (see below), whose sum is σ = 115122204859552. Its totient is φ = 115122022224732.

The previous prime is 115122113542087. The next prime is 115122113542169. The reversal of 115122113542141 is 141245311221511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 115122113542141 - 2¹⁵ = 115122113509373 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 115122113542097 and 115122113542106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115122113542171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43740831 + ... + 46297996.

It is an arithmetic number, because the mean of its divisors is an integer number (28780551214888).

Almost surely, 2^{115122113542141} is an apocalyptic number.

It is an amenable number.

115122113542141 is a deficient number, since it is larger than the sum of its proper divisors (91317411).

115122113542141 is an equidigital number, since it uses as much as digits as its factorization.

115122113542141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 91317410.

The product of its digits is 9600, while the sum is 34.

Adding to 115122113542141 its reverse (141245311221511), we get a palindrome (256367424763652).

The spelling of 115122113542141 in words is "one hundred fifteen trillion, one hundred twenty-two billion, one hundred thirteen million, five hundred forty-two thousand, one hundred forty-one".