Base | Representation |
---|---|
bin | 1010011110001001010010… |
… | …0010101000110110001101 |
3 | 1111202122002002001110222102 |
4 | 2213202110202220312031 |
5 | 3002112113120231303 |
6 | 40253000133324445 |
7 | 2265533661151535 |
oct | 247422442506615 |
9 | 44678062043872 |
10 | 11513004461453 |
11 | 3739701969810 |
12 | 135b369a96725 |
13 | 656896846421 |
14 | 2bb3379664c5 |
15 | 14e72dd21288 |
hex | a78948a8d8d |
11513004461453 has 8 divisors (see below), whose sum is σ = 12560508842880. Its totient is φ = 10465644682080.
The previous prime is 11513004461437. The next prime is 11513004461461. The reversal of 11513004461453 is 35416440031511.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11513004461453 - 24 = 11513004461437 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11513004461423) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35984000 + ... + 36302537.
It is an arithmetic number, because the mean of its divisors is an integer number (1570063605360).
Almost surely, 211513004461453 is an apocalyptic number.
It is an amenable number.
11513004461453 is a deficient number, since it is larger than the sum of its proper divisors (1047504381427).
11513004461453 is a wasteful number, since it uses less digits than its factorization.
11513004461453 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 72301027.
The product of its (nonzero) digits is 86400, while the sum is 38.
Adding to 11513004461453 its reverse (35416440031511), we get a palindrome (46929444492964).
The spelling of 11513004461453 in words is "eleven trillion, five hundred thirteen billion, four million, four hundred sixty-one thousand, four hundred fifty-three".
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