Base | Representation |
---|---|
bin | 1010011110001001010100… |
… | …1111001100000101010011 |
3 | 1111202122002220000211002110 |
4 | 2213202111033030011103 |
5 | 3002112124112440430 |
6 | 40253001231520403 |
7 | 2265534162342240 |
oct | 247422517140523 |
9 | 44678086024073 |
10 | 11513016140115 |
11 | 37397085160a6 |
12 | 135b371989103 |
13 | 6568990a5089 |
14 | 2bb3393265c7 |
15 | 14e72ed7b7b0 |
hex | a78953cc153 |
11513016140115 has 64 divisors (see below), whose sum is σ = 21193554438144. Its totient is φ = 5227884254208.
The previous prime is 11513016140099. The next prime is 11513016140117. The reversal of 11513016140115 is 51104161031511.
It is not a de Polignac number, because 11513016140115 - 24 = 11513016140099 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11513016140117) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 12311602 + ... + 13213688.
It is an arithmetic number, because the mean of its divisors is an integer number (331149288096).
Almost surely, 211513016140115 is an apocalyptic number.
11513016140115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11513016140115 is a deficient number, since it is larger than the sum of its proper divisors (9680538298029).
11513016140115 is a wasteful number, since it uses less digits than its factorization.
11513016140115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 902916.
The product of its (nonzero) digits is 1800, while the sum is 30.
Adding to 11513016140115 its reverse (51104161031511), we get a palindrome (62617177171626).
The spelling of 11513016140115 in words is "eleven trillion, five hundred thirteen billion, sixteen million, one hundred forty thousand, one hundred fifteen".
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