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11513021119 is a prime number
BaseRepresentation
bin10101011100011101…
…01100001010111111
31002201100210001220121
422232032230022333
5142034313133434
65142231555411
7555206031145
oct125616541277
932640701817
1011513021119
114978889196
12229382bb67
1311162bb442
147b3095595
15475b2a7b4
hex2ae3ac2bf

11513021119 has 2 divisors, whose sum is σ = 11513021120. Its totient is φ = 11513021118.

The previous prime is 11513021099. The next prime is 11513021131. The reversal of 11513021119 is 91112031511.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11513021119 is a prime.

It is a super-2 number, since 2×115130211192 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11513021093 and 11513021102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11513021419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5756510559 + 5756510560.

It is an arithmetic number, because the mean of its divisors is an integer number (5756510560).

Almost surely, 211513021119 is an apocalyptic number.

11513021119 is a deficient number, since it is larger than the sum of its proper divisors (1).

11513021119 is an equidigital number, since it uses as much as digits as its factorization.

11513021119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 270, while the sum is 25.

The spelling of 11513021119 in words is "eleven billion, five hundred thirteen million, twenty-one thousand, one hundred nineteen".