1151340083 has 2 divisors, whose sum is σ = 1151340084. Its totient is φ = 1151340082.

The previous prime is 1151339999. The next prime is 1151340143. The reversal of 1151340083 is 3800431511.

It is a strong prime.

It is an emirp because it is prime and its reverse (3800431511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1151340083 - 2²⁰ = 1150291507 is a prime.

It is not a weakly prime, because it can be changed into another prime (1151340383) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575670041 + 575670042.

It is an arithmetic number, because the mean of its divisors is an integer number (575670042).

Almost surely, 2^1151340083 is an apocalyptic number.

1151340083 is a deficient number, since it is larger than the sum of its proper divisors (1).

1151340083 is an equidigital number, since it uses as much as digits as its factorization.

1151340083 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 26.

The square root of 1151340083 is about 33931.4026087929. The cubic root of 1151340083 is about 1048.0963491022.

Adding to 1151340083 its reverse (3800431511), we get a palindrome (4951771594).

The spelling of 1151340083 in words is "one billion, one hundred fifty-one million, three hundred forty thousand, eighty-three".