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1151340143 is a prime number
BaseRepresentation
bin100010010100000…
…0000111001101111
32222020110010202112
41010220000321233
54324220341033
6310125114235
740350141542
oct10450007157
92866403675
101151340143
115409a0988
122816b897b
131546b8075
14acca4859
156b127c48
hex44a00e6f

1151340143 has 2 divisors, whose sum is σ = 1151340144. Its totient is φ = 1151340142.

The previous prime is 1151340083. The next prime is 1151340161. The reversal of 1151340143 is 3410431511.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (3410431511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1151340143 - 220 = 1150291567 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1151340173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575670071 + 575670072.

It is an arithmetic number, because the mean of its divisors is an integer number (575670072).

Almost surely, 21151340143 is an apocalyptic number.

1151340143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1151340143 is an equidigital number, since it uses as much as digits as its factorization.

1151340143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720, while the sum is 23.

The square root of 1151340143 is about 33931.4034929297. The cubic root of 1151340143 is about 1048.0963673087.

Adding to 1151340143 its reverse (3410431511), we get a palindrome (4561771654).

The spelling of 1151340143 in words is "one billion, one hundred fifty-one million, three hundred forty thousand, one hundred forty-three".