115140130039999 has 4 divisors (see below), whose sum is σ = 115140156126664. Its totient is φ = 115140103953336.

The previous prime is 115140130039973. The next prime is 115140130040017. The reversal of 115140130039999 is 999930031041511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 115140130039999 - 2²³ = 115140121651391 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115140130039199) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4601457 + ... + 15857290.

It is an arithmetic number, because the mean of its divisors is an integer number (28785039031666).

Almost surely, 2^{115140130039999} is an apocalyptic number.

115140130039999 is a deficient number, since it is larger than the sum of its proper divisors (26086665).

115140130039999 is an equidigital number, since it uses as much as digits as its factorization.

115140130039999 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26086664.

The product of its (nonzero) digits is 1180980, while the sum is 55.

The spelling of 115140130039999 in words is "one hundred fifteen trillion, one hundred forty billion, one hundred thirty million, thirty-nine thousand, nine hundred ninety-nine".