115140130040000 has 140 divisors (see below), whose sum is σ = 307472418880704. Its totient is φ = 42513278592000.

The previous prime is 115140130039973. The next prime is 115140130040017. The reversal of 115140130040000 is 40031041511.

It is a happy number.

115140130040000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×115140130040000² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 110191664 + ... + 111231663.

Almost surely, 2^{115140130040000} is an apocalyptic number.

115140130040000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

115140130040000 is an abundant number, since it is smaller than the sum of its proper divisors (192332288840704).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

115140130040000 is an equidigital number, since it uses as much as digits as its factorization.

115140130040000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 221423372 (or 221423347 counting only the distinct ones).

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 115140130040000 its reverse (40031041511), we get a palindrome (115180161081511).

The spelling of 115140130040000 in words is "one hundred fifteen trillion, one hundred forty billion, one hundred thirty million, forty thousand".