1151454403 has 4 divisors (see below), whose sum is σ = 1256132088. Its totient is φ = 1046776720.

The previous prime is 1151454401. The next prime is 1151454413. The reversal of 1151454403 is 3044541511.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3044541511 = 11 ⋅276776501.

It is not a de Polignac number, because 1151454403 - 2¹ = 1151454401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1151454401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52338826 + ... + 52338847.

It is an arithmetic number, because the mean of its divisors is an integer number (314033022).

Almost surely, 2^1151454403 is an apocalyptic number.

1151454403 is a deficient number, since it is larger than the sum of its proper divisors (104677685).

1151454403 is a wasteful number, since it uses less digits than its factorization.

1151454403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 104677684.

The product of its (nonzero) digits is 4800, while the sum is 28.

The square root of 1151454403 is about 33933.0871421980. The cubic root of 1151454403 is about 1048.1310374944.

Adding to 1151454403 its reverse (3044541511), we get a palindrome (4195995914).

It can be divided in two parts, 1151 and 454403, that added together give a palindrome (455554).

The spelling of 1151454403 in words is "one billion, one hundred fifty-one million, four hundred fifty-four thousand, four hundred three".