Base | Representation |
---|---|
bin | 11010001011100110110000… |
… | …000110000000011111011000 |
3 | 120002200220211202221110211011 |
4 | 122023212300012000133120 |
5 | 110043031002021301402 |
6 | 1044521402333143304 |
7 | 33153035243031352 |
oct | 3213466006003730 |
9 | 502626752843734 |
10 | 115146732603352 |
11 | 3376450075a39a |
12 | 10ab825b92ab34 |
13 | 4c333a0a09778 |
14 | 20611bb1480d2 |
15 | d4a36dc50ed7 |
hex | 68b9b01807d8 |
115146732603352 has 16 divisors (see below), whose sum is σ = 216368453624400. Its totient is φ = 57448478303520.
The previous prime is 115146732603349. The next prime is 115146732603359. The reversal of 115146732603352 is 253306237641511.
It is a junction number, because it is equal to n+sod(n) for n = 115146732603296 and 115146732603305.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115146732603359) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15610995852 + ... + 15611003227.
It is an arithmetic number, because the mean of its divisors is an integer number (13523028351525).
Almost surely, 2115146732603352 is an apocalyptic number.
It is an amenable number.
115146732603352 is a deficient number, since it is larger than the sum of its proper divisors (101221721021048).
115146732603352 is a wasteful number, since it uses less digits than its factorization.
115146732603352 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31221999546 (or 31221999542 counting only the distinct ones).
The product of its (nonzero) digits is 2721600, while the sum is 49.
The spelling of 115146732603352 in words is "one hundred fifteen trillion, one hundred forty-six billion, seven hundred thirty-two million, six hundred three thousand, three hundred fifty-two".
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