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11515136550055 = 57513066614261
BaseRepresentation
bin1010011110010001001110…
…0111111010010010100111
31111202211120122221210200221
42213210103213322102213
53002130444424100210
640253551455345211
72265640550463355
oct247442347722247
944684518853627
1011515136550055
11373a5a6424506
12135b863b22207
13656b4648ab08
142bb49aba67d5
1514e8060c61da
hexa79139fa4a7

11515136550055 has 8 divisors (see below), whose sum is σ = 13836563550144. Its totient is φ = 9199842780000.

The previous prime is 11515136550019. The next prime is 11515136550059. The reversal of 11515136550055 is 55005563151511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11515136550055 - 211 = 11515136548007 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11515136549993 and 11515136550020.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11515136550059) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1533303376 + ... + 1533310885.

It is an arithmetic number, because the mean of its divisors is an integer number (1729570443768).

Almost surely, 211515136550055 is an apocalyptic number.

11515136550055 is a deficient number, since it is larger than the sum of its proper divisors (2321427000089).

11515136550055 is an equidigital number, since it uses as much as digits as its factorization.

11515136550055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3066615017.

The product of its (nonzero) digits is 281250, while the sum is 43.

The spelling of 11515136550055 in words is "eleven trillion, five hundred fifteen billion, one hundred thirty-six million, five hundred fifty thousand, fifty-five".

Divisors: 1 5 751 3755 3066614261 15333071305 2303027310011 11515136550055