Base | Representation |
---|---|
bin | 1010011110010001001110… |
… | …0111111010010010100111 |
3 | 1111202211120122221210200221 |
4 | 2213210103213322102213 |
5 | 3002130444424100210 |
6 | 40253551455345211 |
7 | 2265640550463355 |
oct | 247442347722247 |
9 | 44684518853627 |
10 | 11515136550055 |
11 | 373a5a6424506 |
12 | 135b863b22207 |
13 | 656b4648ab08 |
14 | 2bb49aba67d5 |
15 | 14e8060c61da |
hex | a79139fa4a7 |
11515136550055 has 8 divisors (see below), whose sum is σ = 13836563550144. Its totient is φ = 9199842780000.
The previous prime is 11515136550019. The next prime is 11515136550059. The reversal of 11515136550055 is 55005563151511.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11515136550055 - 211 = 11515136548007 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11515136549993 and 11515136550020.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11515136550059) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1533303376 + ... + 1533310885.
It is an arithmetic number, because the mean of its divisors is an integer number (1729570443768).
Almost surely, 211515136550055 is an apocalyptic number.
11515136550055 is a deficient number, since it is larger than the sum of its proper divisors (2321427000089).
11515136550055 is an equidigital number, since it uses as much as digits as its factorization.
11515136550055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3066615017.
The product of its (nonzero) digits is 281250, while the sum is 43.
The spelling of 11515136550055 in words is "eleven trillion, five hundred fifteen billion, one hundred thirty-six million, five hundred fifty thousand, fifty-five".
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