Base | Representation |
---|---|
bin | 10000110000111001010… |
… | …001000011010100110011 |
3 | 11002010112200211110200112 |
4 | 100300321101003110303 |
5 | 122333310033203312 |
6 | 2241121011211535 |
7 | 146141634330032 |
oct | 20607121032463 |
9 | 4063480743615 |
10 | 1152012006707 |
11 | 404624821501 |
12 | 1673265a6bab |
13 | 848326373c3 |
14 | 3da870da719 |
15 | 1ee76ccad22 |
hex | 10c39443533 |
1152012006707 has 2 divisors, whose sum is σ = 1152012006708. Its totient is φ = 1152012006706.
The previous prime is 1152012006619. The next prime is 1152012006709. The reversal of 1152012006707 is 7076002102511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1152012006707 - 236 = 1083292529971 is a prime.
Together with 1152012006709, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1152012006709) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576006003353 + 576006003354.
It is an arithmetic number, because the mean of its divisors is an integer number (576006003354).
Almost surely, 21152012006707 is an apocalyptic number.
1152012006707 is a deficient number, since it is larger than the sum of its proper divisors (1).
1152012006707 is an equidigital number, since it uses as much as digits as its factorization.
1152012006707 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5880, while the sum is 32.
The spelling of 1152012006707 in words is "one trillion, one hundred fifty-two billion, twelve million, six thousand, seven hundred seven".
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