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115201542431132 = 22167172457398849
BaseRepresentation
bin11010001100011001110011…
…000000111010000110011100
3120002220011022120022012202122
4122030121303000322012130
5110044430224330244012
61045002505154042112
733160015420625543
oct3214316300720634
9502804276265678
10115201542431132
113378577744a223
1210b069b7579338
134c385c70b2121
142063ada59515a
15d4b9ca9d4e72
hex68c67303a19c

115201542431132 has 12 divisors (see below), whose sum is σ = 202809901047600. Its totient is φ = 57255856417536.

The previous prime is 115201542431093. The next prime is 115201542431149. The reversal of 115201542431132 is 231134245102511.

It is a junction number, because it is equal to n+sod(n) for n = 115201542431092 and 115201542431101.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86228698757 + ... + 86228700092.

It is an arithmetic number, because the mean of its divisors is an integer number (16900825087300).

Almost surely, 2115201542431132 is an apocalyptic number.

It is an amenable number.

115201542431132 is a deficient number, since it is larger than the sum of its proper divisors (87608358616468).

115201542431132 is a wasteful number, since it uses less digits than its factorization.

115201542431132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 172457399020 (or 172457399018 counting only the distinct ones).

The product of its (nonzero) digits is 28800, while the sum is 35.

Adding to 115201542431132 its reverse (231134245102511), we get a palindrome (346335787533643).

The spelling of 115201542431132 in words is "one hundred fifteen trillion, two hundred one billion, five hundred forty-two million, four hundred thirty-one thousand, one hundred thirty-two".

Divisors: 1 2 4 167 334 668 172457398849 344914797698 689829595396 28800385607783 57600771215566 115201542431132