11520334614053 has 8 divisors (see below), whose sum is σ = 11590286247000. Its totient is φ = 11450421603328.

The previous prime is 11520334613981. The next prime is 11520334614091. The reversal of 11520334614053 is 35041643302511.

It can be written as a sum of positive squares in 4 ways, for example, as 1560105917764 + 9960228696289 = 1249042^2 + 3155983^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11520334614053 - 2⁸ = 11520334613797 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11520334613998 and 11520334614016.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11520334644053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9057068 + ... + 10250421.

It is an arithmetic number, because the mean of its divisors is an integer number (1448785780875).

Almost surely, 2^{11520334614053} is an apocalyptic number.

It is an amenable number.

11520334614053 is a deficient number, since it is larger than the sum of its proper divisors (69951632947).

11520334614053 is a wasteful number, since it uses less digits than its factorization.

11520334614053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19311111.

The product of its (nonzero) digits is 129600, while the sum is 38.

Adding to 11520334614053 its reverse (35041643302511), we get a palindrome (46561977916564).

The spelling of 11520334614053 in words is "eleven trillion, five hundred twenty billion, three hundred thirty-four million, six hundred fourteen thousand, fifty-three".