Base | Representation |
---|---|
bin | 11010001100100010111011… |
… | …001100010001000101110111 |
3 | 120002221002121121101002111011 |
4 | 122030202323030101011313 |
5 | 110100110312341144111 |
6 | 1045011205504453051 |
7 | 33160513326644233 |
oct | 3214427314210567 |
9 | 502832547332434 |
10 | 115211343303031 |
11 | 33789946817358 |
12 | 10b0889191a187 |
13 | 4c394c975c101 |
14 | 206438a0c15c3 |
15 | d4bda115c021 |
hex | 68c8bb311177 |
115211343303031 has 4 divisors (see below), whose sum is σ = 115355899568952. Its totient is φ = 115066787037112.
The previous prime is 115211343303019. The next prime is 115211343303193. The reversal of 115211343303031 is 130303343112511.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 115211343303031 - 25 = 115211343302999 is a prime.
It is a super-2 number, since 2×1152113433030312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 115211343302984 and 115211343303002.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115211343307031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72278131765 + ... + 72278133358.
It is an arithmetic number, because the mean of its divisors is an integer number (28838974892238).
Almost surely, 2115211343303031 is an apocalyptic number.
115211343303031 is a deficient number, since it is larger than the sum of its proper divisors (144556265921).
115211343303031 is an equidigital number, since it uses as much as digits as its factorization.
115211343303031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 144556265920.
The product of its (nonzero) digits is 9720, while the sum is 31.
Adding to 115211343303031 its reverse (130303343112511), we get a palindrome (245514686415542).
The spelling of 115211343303031 in words is "one hundred fifteen trillion, two hundred eleven billion, three hundred forty-three million, three hundred three thousand, thirty-one".
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