115231342510019 has 4 divisors (see below), whose sum is σ = 119204837079360. Its totient is φ = 111257847940680.

The previous prime is 115231342510007. The next prime is 115231342510027. The reversal of 115231342510019 is 910015243132511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-115231342510019 is a prime.

It is a super-3 number, since 3×115231342510019³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (115231342510519) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1986747284627 + ... + 1986747284684.

It is an arithmetic number, because the mean of its divisors is an integer number (29801209269840).

Almost surely, 2^{115231342510019} is an apocalyptic number.

115231342510019 is a deficient number, since it is larger than the sum of its proper divisors (3973494569341).

115231342510019 is an equidigital number, since it uses as much as digits as its factorization.

115231342510019 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3973494569340.

The product of its (nonzero) digits is 32400, while the sum is 38.

The spelling of 115231342510019 in words is "one hundred fifteen trillion, two hundred thirty-one billion, three hundred forty-two million, five hundred ten thousand, nineteen".