Base | Representation |
---|---|
bin | 11010001100110111001111… |
… | …101010001010001110110111 |
3 | 120010000011221011012100121011 |
4 | 122030313033222022032313 |
5 | 110100440003322120210 |
6 | 1045025214504533051 |
7 | 33162215110510345 |
oct | 3214671752121667 |
9 | 503004834170534 |
10 | 115233161520055 |
11 | 33798122612777 |
12 | 10b10b60781187 |
13 | 4c3b595a347b7 |
14 | 2065459a62995 |
15 | d4c72b82dd8a |
hex | 68cdcfa8a3b7 |
115233161520055 has 16 divisors (see below), whose sum is σ = 143053138303200. Its totient is φ = 89004525151360.
The previous prime is 115233161520049. The next prime is 115233161520073. The reversal of 115233161520055 is 550025161332511.
It is not a de Polignac number, because 115233161520055 - 213 = 115233161511863 is a prime.
It is a super-3 number, since 3×1152331615200553 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9994540 + ... + 18175729.
It is an arithmetic number, because the mean of its divisors is an integer number (8940821143950).
Almost surely, 2115233161520055 is an apocalyptic number.
115233161520055 is a deficient number, since it is larger than the sum of its proper divisors (27819976783145).
115233161520055 is a wasteful number, since it uses less digits than its factorization.
115233161520055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28198514.
The product of its (nonzero) digits is 135000, while the sum is 40.
The spelling of 115233161520055 in words is "one hundred fifteen trillion, two hundred thirty-three billion, one hundred sixty-one million, five hundred twenty thousand, fifty-five".
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