Base | Representation |
---|---|
bin | 1010011110110000001111… |
… | …1011000000101101100110 |
3 | 1111210122001221202010212112 |
4 | 2213230003323000231212 |
5 | 3002300023020244410 |
6 | 40301450021321022 |
7 | 2266354104560516 |
oct | 247540373005546 |
9 | 44718057663775 |
10 | 11523463056230 |
11 | 374308952a874 |
12 | 13613a8566172 |
13 | 65787254c648 |
14 | 2bba4a983846 |
15 | 14eb420b9105 |
hex | a7b03ec0b66 |
11523463056230 has 24 divisors (see below), whose sum is σ = 21087844554816. Its totient is φ = 4533821515680.
The previous prime is 11523463056137. The next prime is 11523463056241. The reversal of 11523463056230 is 3265036432511.
11523463056230 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 154806422 + ... + 154880841.
It is an arithmetic number, because the mean of its divisors is an integer number (878660189784).
Almost surely, 211523463056230 is an apocalyptic number.
11523463056230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11523463056230 is a deficient number, since it is larger than the sum of its proper divisors (9564381498586).
11523463056230 is an equidigital number, since it uses as much as digits as its factorization.
11523463056230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 309687392 (or 309687331 counting only the distinct ones).
The product of its (nonzero) digits is 388800, while the sum is 41.
Adding to 11523463056230 its reverse (3265036432511), we get a palindrome (14788499488741).
The spelling of 11523463056230 in words is "eleven trillion, five hundred twenty-three billion, four hundred sixty-three million, fifty-six thousand, two hundred thirty".
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