Base | Representation |
---|---|
bin | 110101101010100001… |
… | …1000100001000010111 |
3 | 102000110111222101012211 |
4 | 1223111003010020113 |
5 | 3342004314000210 |
6 | 124535300054251 |
7 | 11216561405425 |
oct | 1532503041027 |
9 | 360414871184 |
10 | 115243500055 |
11 | 44968a51332 |
12 | 1a402994387 |
13 | ab37933768 |
14 | 581374c115 |
15 | 2ee75ec38a |
hex | 1ad50c4217 |
115243500055 has 16 divisors (see below), whose sum is σ = 151476246720. Its totient is φ = 83779451392.
The previous prime is 115243500023. The next prime is 115243500109. The reversal of 115243500055 is 550005342511.
It is a cyclic number.
It is not a de Polignac number, because 115243500055 - 25 = 115243500023 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23373499 + ... + 23378428.
It is an arithmetic number, because the mean of its divisors is an integer number (9467265420).
Almost surely, 2115243500055 is an apocalyptic number.
115243500055 is a deficient number, since it is larger than the sum of its proper divisors (36232746665).
115243500055 is a wasteful number, since it uses less digits than its factorization.
115243500055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46751978.
The product of its (nonzero) digits is 15000, while the sum is 31.
Adding to 115243500055 its reverse (550005342511), we get a palindrome (665248842566).
The spelling of 115243500055 in words is "one hundred fifteen billion, two hundred forty-three million, five hundred thousand, fifty-five".
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