Base | Representation |
---|---|
bin | 10101011101111000… |
… | …10010001100100001 |
3 | 1002202012021022021122 |
4 | 22232330102030201 |
5 | 142100343121340 |
6 | 5143340102025 |
7 | 555412441244 |
oct | 125674221441 |
9 | 32665238248 |
10 | 11524973345 |
11 | 4984602066 |
12 | 2297834915 |
13 | 1118914772 |
14 | 7b48c725b |
15 | 476bdbdb5 |
hex | 2aef12321 |
11524973345 has 4 divisors (see below), whose sum is σ = 13829968020. Its totient is φ = 9219978672.
The previous prime is 11524973333. The next prime is 11524973389. The reversal of 11524973345 is 54337942511.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 54337942511 = 41 ⋅1325315671.
It can be written as a sum of positive squares in 2 ways, for example, as 1509167104 + 10015806241 = 38848^2 + 100079^2 .
It is a cyclic number.
It is not a de Polignac number, because 11524973345 - 210 = 11524972321 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11524973296 and 11524973305.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1152497330 + ... + 1152497339.
It is an arithmetic number, because the mean of its divisors is an integer number (3457492005).
Almost surely, 211524973345 is an apocalyptic number.
It is an amenable number.
11524973345 is a deficient number, since it is larger than the sum of its proper divisors (2304994675).
11524973345 is an equidigital number, since it uses as much as digits as its factorization.
11524973345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2304994674.
The product of its digits is 453600, while the sum is 44.
The spelling of 11524973345 in words is "eleven billion, five hundred twenty-four million, nine hundred seventy-three thousand, three hundred forty-five".
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