Base | Representation |
---|---|
bin | 110101101010110000… |
… | …0111110001101100111 |
3 | 102000111001201200210011 |
4 | 1223111200332031213 |
5 | 3342013320341020 |
6 | 124540140111051 |
7 | 11220015141001 |
oct | 1532540761547 |
9 | 360431650704 |
10 | 115251340135 |
11 | 44972416738 |
12 | 1a405535487 |
13 | ab3944a169 |
14 | 58147cd371 |
15 | 2ee814a35a |
hex | 1ad583e367 |
115251340135 has 8 divisors (see below), whose sum is σ = 138304444320. Its totient is φ = 92199181344.
The previous prime is 115251340103. The next prime is 115251340153. The reversal of 115251340135 is 531043152511.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 115251340135 - 25 = 115251340103 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 115251340097 and 115251340106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 67326 + ... + 484804.
It is an arithmetic number, because the mean of its divisors is an integer number (17288055540).
Almost surely, 2115251340135 is an apocalyptic number.
115251340135 is a deficient number, since it is larger than the sum of its proper divisors (23053104185).
115251340135 is an equidigital number, since it uses as much as digits as its factorization.
115251340135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 472697.
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 115251340135 its reverse (531043152511), we get a palindrome (646294492646).
The spelling of 115251340135 in words is "one hundred fifteen billion, two hundred fifty-one million, three hundred forty thousand, one hundred thirty-five".
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