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11525214103 = 134121623291
BaseRepresentation
bin10101011101111010…
…01100111110010111
31002202012201112112121
422232331030332113
5142100423322403
65143345200411
7555414463204
oct125675147627
932665645477
1011525214103
114984756a37
122297930107
13111899a220
147b494acab
15476c383bd
hex2aef4cf97

11525214103 has 8 divisors (see below), whose sum is σ = 12714495696. Its totient is φ = 10379179200.

The previous prime is 11525214097. The next prime is 11525214119. The reversal of 11525214103 is 30141252511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11525214103 - 221 = 11523116951 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11525214143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10811113 + ... + 10812178.

It is an arithmetic number, because the mean of its divisors is an integer number (1589311962).

Almost surely, 211525214103 is an apocalyptic number.

11525214103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

11525214103 is a deficient number, since it is larger than the sum of its proper divisors (1189281593).

11525214103 is a wasteful number, since it uses less digits than its factorization.

11525214103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21623345.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 11525214103 its reverse (30141252511), we get a palindrome (41666466614).

The spelling of 11525214103 in words is "eleven billion, five hundred twenty-five million, two hundred fourteen thousand, one hundred three".

Divisors: 1 13 41 533 21623291 281102783 886554931 11525214103