Base | Representation |
---|---|
bin | 1010011110110111111101… |
… | …0111100001111101100111 |
3 | 1111210211102021211121000022 |
4 | 2213231333113201331213 |
5 | 3002313243214130043 |
6 | 40302431323505355 |
7 | 2266456323450524 |
oct | 247557727417547 |
9 | 44724367747008 |
10 | 11525534130023 |
11 | 3743a51601201 |
12 | 136188608825b |
13 | 657b126501b4 |
14 | 2bbba5a6014b |
15 | 14ec13d1a868 |
hex | a7b7f5e1f67 |
11525534130023 has 2 divisors, whose sum is σ = 11525534130024. Its totient is φ = 11525534130022.
The previous prime is 11525534129981. The next prime is 11525534130109. The reversal of 11525534130023 is 32003143552511.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11525534130023 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11525534132023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5762767065011 + 5762767065012.
It is an arithmetic number, because the mean of its divisors is an integer number (5762767065012).
Almost surely, 211525534130023 is an apocalyptic number.
11525534130023 is a deficient number, since it is larger than the sum of its proper divisors (1).
11525534130023 is an equidigital number, since it uses as much as digits as its factorization.
11525534130023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54000, while the sum is 35.
Adding to 11525534130023 its reverse (32003143552511), we get a palindrome (43528677682534).
The spelling of 11525534130023 in words is "eleven trillion, five hundred twenty-five billion, five hundred thirty-four million, one hundred thirty thousand, twenty-three".
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