Base | Representation |
---|---|
bin | 110101101100001101… |
… | …0100110001011111111 |
3 | 102000121110021220021022 |
4 | 1223120122212023333 |
5 | 3342113300004021 |
6 | 124545035054355 |
7 | 11221145555663 |
oct | 1533032461377 |
9 | 360543256238 |
10 | 115300000511 |
11 | 44997931a23 |
12 | 1a4198a13bb |
13 | ab46556897 |
14 | 581b0588a3 |
15 | 2eec55d1ab |
hex | 1ad86a62ff |
115300000511 has 2 divisors, whose sum is σ = 115300000512. Its totient is φ = 115300000510.
The previous prime is 115300000481. The next prime is 115300000549. The reversal of 115300000511 is 115000003511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 115300000511 - 214 = 115299984127 is a prime.
It is a super-2 number, since 2×1153000005112 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 115300000511.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115300000591) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57650000255 + 57650000256.
It is an arithmetic number, because the mean of its divisors is an integer number (57650000256).
Almost surely, 2115300000511 is an apocalyptic number.
115300000511 is a deficient number, since it is larger than the sum of its proper divisors (1).
115300000511 is an equidigital number, since it uses as much as digits as its factorization.
115300000511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 75, while the sum is 17.
The spelling of 115300000511 in words is "one hundred fifteen billion, three hundred million, five hundred eleven", and thus it is an aban number.
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