Base | Representation |
---|---|
bin | 11010001101110101111010… |
… | …011101000111001100101110 |
3 | 120010020121121201012011212001 |
4 | 122031311322131013030232 |
5 | 110103040311041410014 |
6 | 1045120143551002514 |
7 | 33200116450145236 |
oct | 3215657235071456 |
9 | 503217551164761 |
10 | 115300451513134 |
11 | 338137130034a8 |
12 | 10b21bbbb0943a |
13 | 4c44a2a8a0954 |
14 | 206880079ccc6 |
15 | d4e36907e974 |
hex | 68dd7a74732e |
115300451513134 has 4 divisors (see below), whose sum is σ = 172950677269704. Its totient is φ = 57650225756566.
The previous prime is 115300451513129. The next prime is 115300451513167. The reversal of 115300451513134 is 431315154003511.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 115300451513093 and 115300451513102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28825112878282 + ... + 28825112878285.
It is an arithmetic number, because the mean of its divisors is an integer number (43237669317426).
Almost surely, 2115300451513134 is an apocalyptic number.
115300451513134 is a deficient number, since it is larger than the sum of its proper divisors (57650225756570).
115300451513134 is an equidigital number, since it uses as much as digits as its factorization.
115300451513134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 57650225756569.
The product of its (nonzero) digits is 54000, while the sum is 37.
The spelling of 115300451513134 in words is "one hundred fifteen trillion, three hundred billion, four hundred fifty-one million, five hundred thirteen thousand, one hundred thirty-four".
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